July 16, 2015 Please Check My Work. Differentiation and Tangent Lines. Leave a comment Given f(x) = \arctan\left({\frac{\sqrt{1+x}}{\sqrt{1-x}}}\right) I differentiated and this was my answer. \d{y}{x} =… Advertisements Share this:TwitterFacebookGoogleLike this:Like Loading... Related Posted by ronaldconnelly423.